Answer:
The bone is compressed to 4.213*10⁻⁶ m.
Explanation:
Given that ,
Mass of the person M = 85 kg,
Length of femur L =0.65 m
Radius of femur r = 0.02 m
To find,
Compression of the bone l = ?
The Young's Modulus is given by Y= [tex]\frac{FL}{lA}[/tex]
Young's modulus of human femur bone is Y = 9.4 *10⁹ Pa
Rearranging formula ,
l =[tex]\frac{FL}{YA}[/tex]
Weight supported by femur bone is 85 *0.9 =76.5 Kg
Area = π r² =3.14* (0.02)² = 0.001256 m
The length of compressed bone is
l =[tex]\frac{76.5*0.65}{9.4GPa*0.001256}[/tex] = [tex]\frac{49.725}{0.0118GPa}[/tex] =4213.89 *10⁻⁹
l = 4.213*10⁻⁶ m
The bone is compressed to 4.213*10⁻⁶ m.
