Answer:
0.9473 is the probability that the player making at least one shot out of 3 foul shot attempts.
Step-by-step explanation:
We are given the following information:
We treat basketball player making a foul shot as a success.
P(Foul shot) =
[tex]\dfrac{5}{8} = 0.625[/tex]
Then the number of adults follows a binomial distribution, where
[tex]P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}[/tex]
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 3
P(at least one shot out of 3 foul shot attempts)
We have to evaluate:
[tex]P(x \geq 1) =1- P(x = 0)\\\\=1- \binom{3}{0}(0.625)^0(1-0.625)^3\\\\= 1 - 0.0527\\= 0.9473[/tex]
0.9473 is the probability that the player making at least one shot out of 3 foul shot attempts.
