Answer:
Step-by-step explanation:
if center= (h,k)
radius=r
eq. of circle is (x-h)^2+(y-k)^2=r^2
a.
center= (-5,1)
radius=4
eq. of circle is (x+5)^2+(y-1)^2=4^2
b.
center=(5,-1)
radius=4
eq. of circle is (x-5)^2+(y+1)^2=4^2
c.
center=(-5,1)
radius=2
eq. of circle is (x+5)^2+(y-1)^2=2^2
d.
center=(5,-1)
radius=2
eq. of circle is (x-5)^2+(y+1)^2=2^2