Answer:
a. 1.1616
Step-by-step explanation:
Variance is given by:
[tex]\sum x_i^2p_i -\mu^2[/tex]
Where "xi" is each individual number of absences, and "pi" are their respective probability. The mean number of absences is:
[tex]\mu=0*0.6+1*0.2+2*0.12+3*0.04+4*0.04+5*0\\\mu= 0.72\ absences[/tex]
Applying the given data, the variance is:
[tex]V=0^2*0.6+1^2*0.2+2^2*0.12+3^2*0.04+4^2*0.04+5^2*0 - 0.72^2\\V= 1.1616\ absences[/tex]
The variance of the number of days absent is 1.1616 days
