Answer:
Explanation:
parents are wild type is bw+/bw+, st+/st+
white type bw/bw, st/st
f1 is bw+/bw, st/+st
the wild type will carry the dominant allele while the white type will be recessive type of allele.
thus allowing a heterozygous condition in the offspring . which is mix of parent 1 wild and white allele , as each parent contribute to the allele of each type.