Answer:
The molarity of this CaCO3 solution is 0.98 M
Explanation:
Step 1: Data given
Number of moles calcium carbonate (CaCO3) = 1.2 moles
Volume of the solution = 1.22 L
Step 2: Calculate the molarity of this CaCO3 solution
Molarity = moles / volume
Molarity CaCO3 solution = moles CaCO3 / volume of the solution
Molarity CaCO3 solution = 1.2 moles CaCO3 / 1.22 L
Molarity CaCO3 solution = 0.98 mol/L = 0.98 M
The molarity of this CaCO3 solution is 0.98 M