Assume we choose an American household at random and let the random variable X be the number of cars (including SUVs and light trucks) they own. Here is the probability model if we ignore the few households that own more than five cars. Cars (X) 0 1 2 3 4 5 P(X) 0.09 0.36 0.35 0.13 0.05 0.02 Suppose the cost of gas plummets and the price of cars drastically drops, so that every household purchases an additional 3 cars, so that now the values of X are 3, 4, 5, 6, 7, 8 with the corresponding probabilities remaining the same. What happens to the mean (expected) number of cars owned?

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okpalawalter8 okpalawalter8 · Answer 1 · 2020-04-16T06:04:10+02:00

Answer:

The mean would increase by 3

Step-by-step explanation:

The number cars and their probability is shown on the first uploaded image

The mean for the number of cars[X] owned can be mathematically represented as

[tex]E(x) = \sum [ x P(x= x)][/tex]

From the question we are told that each household purchased additional three cars

Let Z be the random variable for the number of cars when the the additional car where added

So Mathematically

Z = X + 3

The mean for the number of cars[X + 3] owned can be mathematically represented as

[tex]E(Z)= E(X +3) = \sum [ (x+3) P(X= x)][/tex]

[tex]= \sum x P(X =x) + 3 \sum P(X =x)[/tex]

[tex]= E(x) + 3 \sum (P(X = x))[/tex]

From the above equation we can see that the mean would increase by factor of 3