Answer:
There's 21% of chances
Step-by-step explanation:
Here we have to use the definition of a simple probability, where all fishes has the same probability to be chose.
So, we have to divide the possible outcomes with the total of outcomes. The possible outcomes refer to the number of large-blue fishes, and the total number of outcomes represent the total number of fishes. So
P = 3/4 ≈ 0.21 (or 21%)
Therfore, there's 21% of chances to select one fish randomly and be a large, blue fish.
The probability that fish is large and red , [tex]\frac{2}{9}[/tex].
Given that, there are 10 large fish and 5 small fish.
Total fish [tex]=15[/tex]
Probability of large fish is, [tex]P=\frac{10}{15}=\frac{2}{3}[/tex]
Probability of red fish is, [tex]P=\frac{5}{15}=\frac{1}{3}[/tex]
When one fish is selected at random.
The probability that it is a large, red fish,
[tex]P(E)=\frac{2}{3} *\frac{1}{3} =\frac{2}{9}[/tex]
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