Answer:
0.4
Step-by-step explanation:
These are the relative frequencies of each face (data are missing in the text of the problem):
Number Showing on Top Face Frequency
1 0
2 3
3 3
4 6
5 3
6 5
The probability to obtain a certain number when throwing the dice is given by
[tex]p(x_i)=\frac{f_i}{\sum f}[/tex]
where
[tex]f_i[/tex] is the relative frequency of the number [tex]x_i[/tex] to occur
[tex]\sum f[/tex] is the sum of the relative frequencies
Here the sum of the frequencies is:
[tex]\sum f=0+3+3+6+3+5=20[/tex]
For number 5 here, we have:
[tex]f_5 = 3[/tex] (from the table)
So the probability of getting a 5 is
[tex]p(5)=\frac{3}{20}[/tex]
For number 6 here, we have
[tex]f_6=5[/tex]
So the probability of getting a 6 is
[tex]p(6)=\frac{5}{20}[/tex]
So the probability to obtain either a 5 or a 6 in the next rolling is:
[tex]p(5\cup 6)=p(5)+p(6)=\frac{3}{20}+\frac{5}{20}=\frac{8}{20}=0.4[/tex]
