Answer:
CuCO₃ is the formula of the substance that will precipitate out first
the concentration of carbonate ion when this precipitation first begins = 1.212 × 10⁻¹¹ M
Explanation:
[tex]Pb(NO_3)_2 \ + \ Na_2CO_3 -----> PbCO_3 \ + \ 2NaNO\\\\ksp \ of \ PbCO_3 = 1.6*10^{-13} \\\\ \\Cu (CH_3COO)_2 \ + \ Na_2CO_3 ------> CuCO_3 \ + \ Na(C_2H_3O_2)\\\\ksp \ of CuCO_3 = 1.3*10^{-10}\\\\As \ ksp \ of CuCO_3 > PbCO_3\\\\Then \ \ CuCO_3 \ will \ precipitate \ out \ first[/tex]
[tex]PbCO_3 ----> Pb^{2+}_{(aq)} + CO^{2-}_{3(aq)}[/tex]
[tex][Pb^{2+}][/tex] will be [tex][Pb(NO_3)_2] = 1.32 *10^{-2} \ M[/tex]
[tex]ksp = [Pb^{2+}][CO^{2-}_3][/tex]
[tex]1.6*10^{-13} = (1.32*10^{-2})(CO^{2-}_3)\\\\(CO^{2-}_3) = \frac{1.6*10^{-13}}{(1.32*10^{-2})}\\\\(CO^{2-}_3) = 1.212 *10^{-11} \ \ M[/tex]
