Answer:
[tex]Na^+_{ions}=3.33x10^{23}Na^+_{ions}[/tex]
Explanation:
Hello,
In this case, for the given molarity and volume of such solution, the moles of sodium sulfate are computed below:
[tex]n_{Na_2SO_4}=0.850\frac{mol}{L}*0.325L=0.276molNa_2SO_4[/tex]
Now, by using the Avogadro's number, the ions result:
[tex]Na^+_{ions}=0.276molNa_2SO_4*\frac{2molNa^+}{1molNa_2SO_4} *\frac{6.022x10^{23}Na^+_{ions}}{1molNa^+} \\\\Na^+_{ions}=3.33x10^{23}Na^+_{ions}[/tex]
Best regards.
