If DNA of a particular species was analyzed and it was found that it contains 24% C, what would be the percentage of T?

Respuesta :

Answer:

26%

Explanation:

C=G

so that's 48% in C and G

The remaining 52% should be divided because A=T

And 52/2=26

If the DNA of a particular species contains 24% C, then the percentage of T is equal to 26%.

DNA is a double helix molecule composed of two long chains of nucleotides.

In DNA, there are four classes of nucleotides, each one containing one different nitrogenous base: Adenine (A), Guanine (G), Cytosine (C) and Thymine (T).

According to the base pair rules, A always pairs with T, whereas G always pairs with C.

In consequence, in this case, the amount of G + C is equal to 48% (24 C + 24 G = 48%), thereby the content of T is equal to 26% (26 T + 26 A = 52% >> 48 + 52 = 100%)

In conclusion, if the DNA of a particular species contains 24% C, then the percentage of T is equal to 26%.

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