Answer: The volume of neon gas is, 56.7 L
Explanation :
To calculate the volume of gas we are using ideal gas equation:
[tex]PV=nRT[/tex]
where,
P = Pressure of neon gas = 0.37 atm
V = Volume of neon gas = ?
n = number of moles neon = 0.83 mole
R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]
T = Temperature of neon gas = [tex]35^oC=273+35=308K[/tex]
Now put all the given values in above equation, we get:
[tex]0.37atm\times V=0.83mole\times (0.0821L.atm/mol.K)\times 308K[/tex]
[tex]V=56.7L[/tex]
Therefore, the volume of neon gas is, 56.7 L
