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at what temperature in celsius would a gas have volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a pressure of 0.612 atm and a temperature of 28.0c

Respuesta :

Answer:

initial temperature=[tex]-3.31^{\circ}C[/tex]

Explanation:

Assuming that the given follows the ideal gas nature;

[tex]P_1=0.723atm[/tex]

[tex]V_1=13.5L[/tex]

[tex]T_1=?[/tex]

[tex]P_2=0.612atm[/tex]

[tex]V_2=17.8L[/tex]

[tex]T_2=28 ^{\circ}C =273+28K=301K[/tex]

mole of gass will remain same at any emperature:

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

putting all the value we get:

[tex]T_2 =269.7K =-3.31 ^{\circ} C[/tex]

initial temperature=[tex]-3.31^{\circ}C[/tex]

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