In an arcade game a 0.099 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and releasing it. If the spring has a spring constant of 244 N/m and is compressed from its equilibrium position by 4 cm, find the speed with which the disk slides across the surface. Answer in units of m/s.

Respuesta :

Answer:

The speed of disk is 1.98 [tex]\frac{m}{s}[/tex]

Explanation:

Given:

Mass of [tex]m = 0.099[/tex] kg

Spring constant [tex]k = 244 \frac{N}{m}[/tex]

Compression of spring [tex]x = 4 \times 10^{-2}[/tex] m

From energy conservation theorem,

Spring potential energy converted into kinetic energy,

   [tex]\frac{1}{2} m v^{2} = \frac{1}{2} k x^{2}[/tex]

  [tex]v = \sqrt{\frac{k x^{2} }{m} }[/tex]

  [tex]v = \sqrt{\frac{244 \times 16 \times 10^{-4} }{0.099} }[/tex]

  [tex]v = 1.98 \frac{m}{s}[/tex]

Therefore, the speed of disk is 1.98 [tex]\frac{m}{s}[/tex]