Answer: a) [tex]\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}[/tex]
Step-by-step explanation:
Since we have given that
Number of red marbles = 3
Number of yellow marbles = 4
Number of green marbles = 6
Total number of marbles = 3 +4 +6 = 13
a) the marble is red?
Probability of getting a red marble = [tex]\dfrac{3}{13}[/tex]
b) the marble is not yellow?
Probability of not getting yellow = [tex]\dfrac{3+6}{13}=\dfrac{9}{13}[/tex]
c) the marble is either red or green?
Probability of getting either red or green = P(red) + P(green) =[tex]\dfrac{3}{13}+\dfrac{6}{13}=\dfrac{9}{13}[/tex]
d) the marble is neither red nor green?
Probability of getting neither red nor green = P(getting yellow) = [tex]\dfrac{4}{13}[/tex]
Hence, a) [tex]\dfrac{3}{13},\ b)\dfrac{9}{13}\ c)\dfrac{9}{13},\ d)\dfrac{4}{13}[/tex]
