Answer:
Option C) 0.1804
Step-by-step explanation:
We are given the following information in the question:
Mean customers enter the tellers’ queue every five minutes = 2
[tex]\lambda = 2[/tex]
Thus, the number of customers that enter the tellers’ queue is Poisson distributed
Formula:
[tex]P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}[/tex]
We have to evaluate:
[tex]P( x = 2)\\\\= \displaystyle\frac{2^3 e^{-2}}{3!}\\\\= 0.1804[/tex]
0.1804 is the probability that exactly three customers enter the queue in a randomly selected five-minute period.
Thus, the correct answer is
Option C) 0.1804
