Answer:
287.19 kg.m²
Explanation:
Given that :
The mass M of the horizontal platform = 111 kg
The radius R of the uniform disk = 1.67 m
mass of the person standing [tex]m_p[/tex] = 64.7 kg
distance of the person standing [tex]d_p[/tex] = 1.15 m
mass of the dog [tex]m_d[/tex] = 25.7 kg
distance of the dog [tex]d_d[/tex] = 1.35 m
Considering the moment of inertia of the object in the system; the net moment of the inertia can be expressed as:
= [tex]\frac{MR^2}{2}+m_pd_p^2+m_dd_d^2[/tex]
= [tex](\frac{111*1.67^2}{2})+ (64.7 *1.15^2)+ (25.7*1.35^2)[/tex]
= 287.19 kg.m²
