Answer:
It is concluded that the area of the platform where the car is located must be 22 times greater than the area of the platform where the man is located.
Explanation:
The pressure on each platform is equal between them, then:
[tex]\frac{W_{1} }{A_{1} } =\frac{W_{2} }{A_{2} } \\A_{1} =A_{2} \frac{W_{1} }{W_{2} }[/tex]
Where
m₁ = 1650 kg
m₂ = 75 kg
And:
[tex]W_{1} =m_{1} *g=9.8*m_{1} \\W_{2} =m_{2} *g=9.8*m_{2}[/tex]
Replacing:
[tex]A_{1} =A_{2} *(\frac{9.8*m_{1} }{9.8*m_{2} } )=A_{2}*(\frac{m_{1} }{m_{2} } )\\A_{1}=A_{2}*(\frac{1650}{75} )=22A_{2}[/tex]
It is concluded that the area of the platform where the car is located must be 22 times greater than the area of the platform where the man is located.
