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you can use a torque feeler that consists of a meterstick held at the 0 cm end with a weight dangling from various positions along the stick. When the stick is held horizontally, torque produced when a 1 kg object hangs fromt he 50 cm mark. How much torque is exerted when the object is hung from the 75 cm mark

Respuesta :

Answer:

[tex]T=7.3575\ N.m[/tex]

Explanation:

Given:

length of the stick, [tex]l=100\ cm=1\ m[/tex]

position of holding the stick that acts as a hinge, [tex]f=0\ cm[/tex]

mass of the object, [tex]m=1\ kg[/tex]

position of hanging the mass on the meter stick, [tex]x=50\ cm=0.5\ m[/tex]

new position of hanging the mass, [tex]x'=75\ cm=0.75\ m[/tex]

Now the torque in the initial position:

[tex]T=mg.x[/tex]

where:

[tex]g=[/tex] acceleration due to gravity

[tex]T=1\times 9.81\times 0.5[/tex]

[tex]T=4.905\ N.m[/tex]

Now when the mass is at the new position:

[tex]T=mg.x'[/tex]

[tex]T=1\times 9.81\times 0.75[/tex]

[tex]T=7.3575\ N.m[/tex]

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