The electric potential energy of q₂ will be 0.67387 J.
What is the electrical potential difference?
The amount of work performed in an electrical field to move a unit charge from one location to another is defined as the electrical potential difference.
Given data;
Charge 1,q₁ = +6.60 × 10⁻⁶ C
Charge 2,q₂ = +3.10 × 10⁻⁶ C
Charge 3,q₃ = +5.30 × 10⁻⁶ C
Distance between the charge 1 and 2,d₁₂=0.350 m
Distance between the charge 2 and 3,d₂₃=0.155 m
The electric potential on charge 2 due to 1;
E₂₁ = (Kq₁q₂)/d₁₂
E₂₁ = (9× 10⁹ × 6.60 × 10⁻⁶ × 3.10 × 10⁻⁶ )/(0.350)
E₂₁ = 0.526 J
The electric potential on charge 3 due to 1;
E₂₃ = (Kq₂q₃)/d₁₃
E₂₃ = (9× 10⁹ ×3.10 × 10⁻⁶ × 5.30 × 10⁻⁶ C )/(0.155)
E₂₃ =0.14787 J
The net electric potential energy on charge 2 is the algebraic sum of the electric potential energy on charge 2 due to 1 and electric potential energy on charge 3 due to 1;
E = E₂₁ + E₂₃
E=0.526+0.14787
E= 0.67387 J
Hence the electric potential energy of q₂ will be 0.67387 J.
To learn more about the electric potential difference refer to the link;
https://brainly.com/question/9383604
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