The figure on the top left is a triangle with base 11 and height 8, for an area of
[tex]A_1=\dfrac{11\cdot 8}{2}=44[/tex]
Immediately below, we have a rectangle with dimensions 11 and 9, for an area of
[tex]A_2=11\cdot 9=99[/tex]
Moving to the right, we have a parallelogram with base 9 and heght 11, which again has height
[tex]A_3=11\cdot 9=99[/tex]
Finally, the rightmost figure is a triangle with base 8 and height 9, for a total of
[tex]A_4=\dfrac{8\cdot 9}{4}=36[/tex]
Sum these areas and you'll get the total area
