Answer:
Amplitude, A = 0.049 meters
Explanation:
Given that,
A harmonic wave travels in the positive x direction at 6 m/s along a taught string. A fixed point on the string oscillates as a function of time according to the equation :
[tex]y = 0.049 \cos(7t)[/tex] .......(1)
The general equation of a wave is given by :
[tex]y=A\cos(\omega t)[/tex] .......(2)
A is amplitude of wave
On comparing equation (1) and (2) we get :
A = 0.049 meters
So, the amplitude of the wave is 0.049 meters.
