Respuesta :
Answer:
5.82 mm
Explanation:
length of the track, L = 23 m
Initial temperature, T = 7 °C
final temperature, T' = 30 °C
Coefficient of linear expansion, α = 11 x 10^-6 / °C
Let the increase in length of the track on the hot day is ΔL.
use the formula of the linear expansion
ΔL = L x α x ΔT
ΔL = L x α x (T' - T)
ΔL = 23 x 11 x 10^-6 x (30 - 7)
ΔL = 5.82 x 10^-3 m
ΔL = 5.82 mm
Thus, the increase in the length of the track is 5.82 mm.
The increase in the length of the rail on a hot day when the temperature is 30 °C is 5.82 mm.
Linear expansion:
Given that the length of the track, L = 23 m
at the Initial temperature, T = 7 °C
The final temperature of the rail is, T' = 30 °C
The coefficient of linear expansion is given to be, α = 11 x 10⁻⁶ / °C
The linear expansion is given by:
ΔL = LαΔT
where ΔT is the temperature difference
ΔT = 30° - 7° = 23°
ΔL = 23 × 11 × 10⁻⁶ × 23
ΔL = 5.82 x 10⁻³ m
ΔL = 5.82 mm
So, the increase in the length of the track is 5.82 mm.
Learn more about linear expansion:
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