Answer:
t = 50,000s
Explanation:
Reaction is second order.
Initial conc. [A]o = 0.020 M
Rate constant = 1.0x10-3 M-1s-1
Final conc. [A] = 0.010M
Time = ?
1 / [A] = kt + 1 / [A]o
Substituting the values;
1 / 0.010 = 1.0x10-3 * t + (1/0.020)
100 - 50 = 1.0x10-3 * t
t = 50 / (1.0x10-3)
t = 50,000s
Answer:
Time required is 50000s
Explanation:
General formula of a second-order reaction is:
[tex]\frac{1}{[A]} =\frac{1}{[A]_0} +Kt[/tex]
Where [A] is concentration of reactant after time t passed, [A]₀ is initial concentration of reactant and K is rate constant of reaction.
Replacing:
[tex]\frac{1}{[0.010M]} =\frac{1}{[0.020M]} +1.0x10^{-3}M^{-1}s^{-1}t[/tex]
50M⁻¹ = 1.0x10⁻³M⁻¹s⁻¹ t
50000s = t
Thus, after 50000s, the reactant concentration decrease from 0.020M to 0.010M
