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The steel water pipe has an inner diameter of 12 in. and a wall thickness of 0.25 in. If the valve A is closed and the water pressure is 300 psi, determine the longitudinal and hoop stress developed in the wall of the pipe at point B. Draw the state of stress on a volume element located on the wall.

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sahir9397

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The hoop stress and longitudinal stress developed in the wall of the pipe at point B are respectively; σ_hoop = 7200 psi and σ_long = 3600 psi

What are the Hoop and Longitudinal Stress?

For normal stress, since valve A is closed it means that;

hoop stress = 2 * longitudinal stress

Hoop stress is gotten from the formula;

σ_hoop = pr/t

where;

p is internal pressure

r is radius

t is thickness

We are given;

p = 300 psi

r = d/2 = 12/2 = 6 in

t = 0.25 in

Thus;

σ_hoop = (300 * 6)/0.25

σ_hoop = 7200 psi

Thus;

σ_long = 7200/2

σ_long = 3600 psi

For the diagram showing the state of stress on the volume element, the hoop stress pulls it vertically upwards while the longitudinal stress pulls it horizontally sideways.

Read more about stress at; https://brainly.com/question/19953629

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