Answer: 4.29 m/s
Explanation:
Given
Depth of the well, s = 8.23 m
Time taken to reach the well, t = 0.93 s
Speed of sound = 343 m/s
To solve this, we would be using one of l the laws of motion.
S = ut + 1/2gt², where
S = depth of the well
u = initial speed of toss
g = acceleration due to gravity
t = time taken to reach the well
We would then have
8.23 = 0.93 u + 1/2 * 9.8 * 0.93²
8.23 = 0.93 u + 4.9 * 0.8649
8.23 = 0.93 u + 4.23801
0.93 u = 8.23 - 4.23801
0.93 u = 3.99199
u = 3.99199 / 0.93
u = 4.29 m/s
Therefore, the initial speed of the coin is 4.29 m/s