Answer:
The period of oscillation of the spring T = 0.702 sec
Explanation:
Mass = 0.5 kg
Spring constant k = 40 [tex]\frac{N}{m}[/tex]
Compression of spring = 0.35 m
Period of oscillation
[tex]T = 2 \pi \sqrt{\frac{m}{k} }[/tex]
Put all the values in above equation
[tex]T = 2 \pi \sqrt{\frac{0.5}{40} }[/tex]
T = 0.702 sec
This is the period of oscillation of the spring.
