Respuesta :
Explanation:
Given that,
Frequency of train horn, f = 218 Hz
Speed of train, [tex]v_t = 31.7 m/s[/tex]
The speed of sound, V = 344 m/s (say)
The speed of the observed person, [tex]V_o=0\ m/s[/tex]
(a) When the train approaches you, the Doppler's effect gives the frequency as follows :
[tex]f'=f(\dfrac{V}{V-v_t})\\\\f'=218\times (\dfrac{344}{344-31.7})\\\\f'=240.12\ Hz[/tex]
(b) When the train moves away from you, the Doppler's effect gives the frequency as follows :
[tex]f'=f(\dfrac{V}{V+v_t})\\\\f'=218\times (\dfrac{344}{344+31.7})\\\\f'=199.6\ Hz[/tex]
Hence, this is the required solution.
The frequency do you hear as the train approaches you and what frequency while it recedes is 240.12Hz and 199.6 Hz.
- The calculation is as follows:
When the train approaches you, the Doppler's effect should be
[tex]= 218 \times 344 \div (344 - 31.7)[/tex]
= 240.12Hz
And,
When the train moves away from you, the Doppler's effect should be
[tex]= 218 \times 344 \div (344 + 31.7)[/tex]
= 199.6 Hz
Here we assume the speed of sound, V = 344 m/s
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