Answer:
[tex]697.6 \ in^2[/tex]
Step-by-step explanation:
-Given the dimensions of the box is 8.7 in, 14 in and 10 in.
Let length=14 in, width=10 in and height =8.7 in
#The surface area of a rectangular prism is calculated as:
[tex]Surface \ Area=2(wl+hl+hw)\\\\l=length, w=width, h=height\\\\\therefore Surface \ Area=2(14\times 10+10\times 8.7+14\times 8.7)\\\\=697.6 \ in^2[/tex]
Hence, the wrapping paper needed has an area of [tex]697.6 \ in^2[/tex]
