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A student in lab titrated a diprotic weak acid with 0.100 M NaOH. To reach the equivalence point required 22.58 mL of NaOH solution. How many moles of diprotic acid were present in the titration

Respuesta :

Answer:

0.0023 moles of Hâ‚‚A

Explanation:

moles Hâ‚‚A in soln = moles NaOH used in titration

moles = Molarity x Volume in Liters

moles Hâ‚‚A = moles NaOH used

Which is = (0.100M)(0.02258L) = 0.0023 mol Hâ‚‚A

The number of moles in a diprotic acid is 0.0023 moles of Hâ‚‚A. This can be identified using law of dilution.

Law of dilution:

While performing titrations, the law of dilution is used.

Molarity is defined as the quantity of moles of solute partitioned by the volume of the arrangement in liters.

Moles of acid = Moles of base

n= M /V

Moles Hâ‚‚A = moles NaOH used

= (0.100M)(0.02258L)

= 0.0023 mol Hâ‚‚A

Find more information about Molarity here:

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