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Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?

Respuesta :

apologiabiology
it is in form
0=ax^2+bx+c
0=-3x^2-2x+6
a=-3
b=-2
c=6

so
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]
x=[tex] \frac{-(-2)+/- \sqrt{(-2)^2-4(-3)(6)} }{2(-3)} [/tex]
x=[tex] \frac{2+/- \sqrt{4+72} }{-6} [/tex]
x=[tex] \frac{2+/- \sqrt{76} }{-6} [/tex]
x=[tex] \frac{2+/- 2\sqrt{19} }{-6} [/tex]
x=[tex] \frac{1+/- \sqrt{19} }{-3} [/tex]
x=[tex] \frac{1+ \sqrt{19} }{-3} [/tex] or [tex] \frac{1- \sqrt{19} }{-3} [/tex]




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