Respuesta :
l×w=64 ft^2...(1)
2w+8= l...(2)
l=64-w...(1a)
2w+8= 64-w
2w+w+8=64
3w=64-8
3w÷3= 56÷3
w=18.6'
l×w= 64
l×18.6= 64
l= 64÷18.6
l= 3.44 to the nearest hundredths.
2w+8= l...(2)
l=64-w...(1a)
2w+8= 64-w
2w+w+8=64
3w=64-8
3w÷3= 56÷3
w=18.6'
l×w= 64
l×18.6= 64
l= 64÷18.6
l= 3.44 to the nearest hundredths.
Answer:
Length = 16 feet , width = 4 feet .
Step-by-step explanation:
Given : The area of a rectangular wall of a barn is 64 square feet. Its length is 8 feet longer than twice its width.
To find : Find the length and width of the wall of the barn.
Solution : We have given
Area of rectangle = 64 square feet.
According to question :
Let width = W.
Length is 8 feet longer than twicw its width .
Length = 2W + 8
L = 2W + 8.
Area of rectangle = length * width.
Plug the values.
64 = (2W +8 )W .
64 = 2W² + 8W.
On subtracting both sides by 64.
2W² + 8W- 64 = 0
On taking 2 common from all.
W² + 4 W- 32 = 0
On factoring
W² + 8W -4W - 32 = 0
W (W +8) -4 ( W + 8) = 0
On grouping
(W+8)( W -4) = 0
W = -8 feet, W = 4 feet. ( ignore negative value)
Width = 4 feet.
Length = 2 (4)+ 8.
Length = 16 feet.
Therefore, Length = 16 feet , width = 4 feet .