Respuesta :
Maximum or minimum value for a quadratic function:
y = -2x² + 4x - 1, a = -2, b = 4, c = -1
y[tex] _{min or max} [/tex] = (4ac - b²)/4a
= (4*(-2)(-1) - 4²) / 4*(-2)
= (8 - 16) /-8 = -8/-8 = 1.
Since the value it positive, it is a maximum.
C. 1
y = -2x² + 4x - 1, a = -2, b = 4, c = -1
y[tex] _{min or max} [/tex] = (4ac - b²)/4a
= (4*(-2)(-1) - 4²) / 4*(-2)
= (8 - 16) /-8 = -8/-8 = 1.
Since the value it positive, it is a maximum.
C. 1