Respuesta :
The exponential function that goes through (1, 8) and (4, 64) is determined by substituting the points to the given functions:
a. y = f(x) = 4(2)^1 = 8 y = f(x) = 4(2)^4 = 64
Since a already answered the question, the answer is A. f(x)=4(2)x
a. y = f(x) = 4(2)^1 = 8 y = f(x) = 4(2)^4 = 64
Since a already answered the question, the answer is A. f(x)=4(2)x
Answer:
[tex]f(x)=4(2)^x[/tex] is the correct exponential graph.
Step-by-step explanation:
We have been given the points (1, 8) and (4, 64) and we have to determine from which exponential function these point are passing through.
The y-coordinate in both the points is greater than the y-coordinate. Hence, we must have positive exponent on x. Then only we can get a higher value.
Hence, options c and d can be discarded.
Let us substitute the values for x and y in the first option.
For x = 1
[tex]y=4(2)^1=8[/tex]
And for x=4.
[tex]y=4(2)^4=64[/tex]
It satisfied the equation.
Therefore, [tex]f(x)=4(2)^x[/tex] is the correct exponential graph.