shatwh0itaSchi
contestada

If someone can help me understand, and figure this problem. . If each substance costs the same amount per kilogram (kg), which would be most cost-effective as a way to lower the freezing point of water? (Assume complete dissociation for all ionic compounds.) Explain. Ill post the 5 molecules as a drawing.

Respuesta :

NaCl would be the most cost-effective as a way to lower the freezing point of water. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

mahima6824soni

The most cost-effective as a way to lower the freezing point of water is [tex]\rm SrCl_2[/tex] because it forms three ions in the water.

What is the freezing point?

The temperature at which the liquid becomes solid is called the freezing point.

The [tex]\rm SrCl_2[/tex] will be most effective because the more ions in the solution, the more water molecules will be bound by the SrCl2 ions, making it impossible for them to escape.

It doesn't matter what kind of substance it is, how heavy or light it is, as long as the number of ions dissociated in the solution is large enough.

Thus, The correct option is [tex]\rm SrCl_2[/tex]

Learn more about freezing point, here:

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