Respuesta :
217 ml of 0.05 M HCl will be required to react with 5 gm of MnO2 according to the equation given.
Explanation:
The balanced chemical equation is given as:
4HCl(aq) + MnO2(s) → 2H2O(l) + MnCl2(aq) + Cl2(g)
This shows that 4 moles of HCl reacts with 1 mole of MnO2
the mass of Manganese oxide is given as 5 grams
molar mass of MnO2 = 86.93 grams/mole
number of moles of MnO2 is given by
number of moles = [tex]\frac{mass}{atomic mass of one mole}[/tex]
number of moles= [tex]\frac{5}{86.93}[/tex]
= 0.0575 moles of MnO2
From the equation:
4 moles of HCl reacts with 1 mole of MnO2
x moles of HCl reacts with [tex]\frac{0.0575}{x}[/tex] moles of MnO2
[tex]\frac{1}{4}[/tex] = [tex]\frac{0.0575}{x}[/tex]
= 0.23 moles of HCl will react
atomic mass of HCl = 36.46 Grams/mole
mass = 0.23 x 36.46
= 8.3858 grams.of HCl
molarity of HCl = [tex]\frac{number of moles}{volume in liters}[/tex]
volume is 1 litre
so molarity is 0.23 M
Using the formula
M1V1 = M2V2
0.05 x 1 = 0.23 X x
x = 0.217 litre
so 217 ml of 0.05 M HCl will be required to react with 5 gm of MnO2.
