Solution:
The vertical leap l measured in feet is related to the hang time t measured in seconds by the equation:
[tex]L = 4t^2[/tex]
Where,
L is the vertical leap in feet
t is the hang time in seconds
From given,
L = 2 feet 2 inches
[tex]1\ inch = \frac{1}{12}\ feet\\\\2\ inches = \frac{2}{12} = 0.1667\ feet[/tex]
Therefore,
L = 2 feet + 0.1667 feet = 2.1667 feet
Substituting in equation,
[tex]2.1667 = 4 \times t^2\\\\t^2 = \frac{2.1667}{4}\\\\t^2 = 0.541675\\\\t = 0.73598 \approx 0.736[/tex]
Thus the hang time for this leap is 0.736 seconds
