Answer:
4t^2-32t+64=4(t^2-8x+16)
Step-by-step explanation:
f(x)=4x^2-8x+4
f(t-3)=4(t-3)^2 - 8(t-3)+4=
4(t^2-2*t*3+9)-8t+24+4=
4(t^2-6t+9)-8t+28=
4t^2-24t+36-8t+28=