For this case we have that by definition, the equation of the line of the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It is the slope of the line
b: It is the cut point with the y axis
We have the following equation:
[tex]x-11y = 9[/tex]
We manipulate algebraically:
[tex]x-9 = 11y\\\frac {x-9} {11} = y\\y = \frac {x} {11} - \frac {9} {11}[/tex]
Thus, the equation in the slope-intersection form is given by:
[tex]y = \frac {x} {11} - \frac {9} {11}[/tex]
Answer:
[tex]y = \frac {x} {11} - \frac {9} {11}[/tex]
