Answer:
0.35
Step-by-step explanation:
we know that
The formula to use for uniform distribution is equal to
[tex]P( X < x) = \frac{x-a}{b-a}[/tex]
where,
b is the upper limit of the distribution which is 5 minutes in this case.
a is the lower limit of the distribution which is 0 minutes in this case.
x is the concerned value which is 1.75 minutes in this case.
substitute the given values
[tex]P( X< 1.75) = \frac{1.75-0}{5-0}=0.35[/tex]
That means
The probability that a randomly selected passenger has a waiting time less than 1.75 minutes is 0.35
