Answer:
Part a) In the day 5 will be a zombie population over 2,000
Part b) [tex]590,490\ zombies[/tex]
Step-by-step explanation:
we know that
The equation of a exponential growth function is equal to
[tex]P=a(1+r)^x[/tex]
where
P is the population of zombie
x is the number of days
a is the initial value
r is the rate of change
we have
[tex]a=10\\r=200\%=200/100=2[/tex]
substitute
[tex]P=10(1+2)^x[/tex]
[tex]P=10(3)^x[/tex]
Part a) On what day will there be a zombie population over 2,000?
For P=2,000
substitute in the exponential equation
[tex]2,000=10(3)^x[/tex]
solve for x
[tex]200=3^x[/tex]
Apply log both sides
[tex]log(200)=xlog(3)[/tex]
[tex]x=log(200)/log(3)[/tex]
[tex]x=4.8\ days[/tex]
therefore
In the day 5 will be a zombie population over 2,000
Part b) If a cure is not found and the virus continues to spread, how many new zombie will there be on day 10?
For x=10 days
substitute in the equation
[tex]P=10(3)^{10}= 590,490\ zombies[/tex]