A small acting club has 6 members. Three of the members are to be chosen for a trip to see a Broadway play. How many different 2 member groups are possible?

Respuesta :

Answer:

15 ways

Step-by-step explanation:

C²₆ = [tex]\frac{6!}{2!}[/tex] = [tex]\frac{6!}{4!2!}[/tex] = [tex]\frac{1*2*3*4*5*6}{1*2*3*4*1*2}[/tex] = [tex]\frac{5*6}{1*2}[/tex] = [tex]\frac{30}{2}[/tex] = 15

Another way is that you choose the first member from the 6. Then you have remaining 5 members.

6 × 5 = 30

But since 2 people can be chosen in 2 ways (but they still form the same team), divide the product by 2.

30 ÷ 2 = 15