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A gas at STP occupies 0.028 L of space. If the pressure changes to 3.8 atm and the temperature increases to 203 C, what is the new volume?


Show your work. Don't forget to convert C to kelvin

Respuesta :

Officialalehpeter

Answer:

9.76L

Explanation:

The ideal gas formula is p1v1/t1=p2v2/t2

Cross mutiply

P1v1t2=p2v2t1

Make v2 the subject of formula

P1v1t2/p2t2=v2

P1=760 ATM

V1=0.028L

T1=273k

P2=3.8 ATM

V2=?

T2=203°c to Kelvin equals to 273+203=476k

Substitute the values given into the formula

760×0.028×476/3.8×273

=10129.28/1037.4

=9.76

Therefore the V2 is 9.76L
YOUR answer will be 9.76L

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