The velocity of a particle on a line at time t is v=5t^2/3+6t. How many meters did the particle travel from t=1 and t=8?

The velocity of a particle on a line at time t is v5t236t How many meters did the particle travel from t1 and t8 class=

Respuesta :

Answer:I keep geting t=0 i dont know why, sorry hope its right.

Answer:

D) 282

Step-by-step explanation:

Step 1: Write out the integral

[tex]\int\limits^8_1 {5t^\frac{2}{3} + 6t } \, dx[/tex]

Step 2: Find the anti-derivative for each term starting with [tex]5t^\frac{2}{3}[/tex]. To do this you add one to [tex]\frac{2}{3}[/tex] and multiply 5 by the reciprocal of that number. Then you do the same to 6t. It should equal this:

[tex]\frac{3}{5} * 5t^\frac{5}{3} + \frac{1}{2} * 6t^2[/tex][tex]]_1^{8}[/tex]

Step 3: Simplify

[tex]3t^\frac{5}{3} + 3t^2[/tex][tex]]_1^{8}[/tex]

Step 4: Solve the definite integral

[tex](3(8)^\frac{5}{3} + 3(8)^2)-(3(1)^\frac{5}{3} + 3(1)^2)[/tex]

[tex](96+192)-(3+3)[/tex]

[tex](288-6)=282[/tex]

Step 5: 282 would be your answer!