Respuesta :
Answer:
Both are 160,000 mg.
Explanation:
So the total amounts of buffer are going to be expressed in mg (in your case). This means you can take the concentrations (in mg/L) and multiply by the volumes (in L) to get your amounts mg.
For Squirrel Lake:
2 mg/L * 80,000 L = 160,000 mg
For Moose Lake:
1.6 mg/L * 100,000 L = 160,000 mg
Concentration is the amount of the solute dissolved in a solution. The total amount of buffer in Squirrel lake and Moose Lake is 160,000 mg.
What is buffer?
A solution that remains unchanged even when acid or base solution is added to them is called a buffer. They neutralize the added acid or base.
The amount of buffer for Squirrel lake is:
[tex]\begin{aligned}&= \rm concentrations \times volumes\\\\&= 2 \times 80,000\\\\&= 160,000\;\rm mg\end{aligned}[/tex]
And, for the Mosse lake will be:
[tex]\begin{aligned}&=\rm concentrations \times volumes\\\\&= 1.6 \times 100,000\\\\&= 160,000\;\rm mg\end{aligned}[/tex]
Therefore, the total amount of buffer for Squirrel lake and Moose Lake is 160,000 mg.
Learn more about buffer here:
https://brainly.com/question/26872640
