Answer: Our required probability is 0.3162.
Step-by-step explanation:
Since we have given that
n = 60
Probability of success = [tex]\dfrac{2}{3}[/tex]
Probability that at most 39 of these relays come from supplier A would be
[tex]P(X\leq 39)=binomcdf(60,\dfrac{2}{3},39)=0.3162[/tex]
Hence, our required probability is 0.3162.