Answer:
[tex]SA=144\ in^2[/tex]
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The surface area of a square pyramid is equal to the area of the square base plus the area of its four congruent triangular faces
so
[tex]SA=b^2+4[\frac{1}{2}bh][/tex]
where
[tex]b=8\ in\\h=5\ in[/tex]
substitute
[tex]SA=8^2+4[\frac{1}{2}(8)(5)][/tex]
[tex]SA=64+80=144\ in^2[/tex]
