Answer:
The inlet velocity is 5.015
Explanation:
Given that,
Mass flow rate m, = 5227kg/h
Pressure P₁ = 102kPa
Inlet area A₁ = 43cm² = 0.043m²
Exit velocity v₂ = 427m/s
For CO₂ gas
R = 0.1889KJ/Kg.k
R is specific gas constant
Calculate the density
[tex]p_1 = \frac{P_1}{RT_1} \\= \frac{1020}{0.1889 (530 + 273) } \\= 6.724kg/m^2[/tex]
Calculate the inlet velocity
[tex]m = p_1A_1v_1\\v_1 = \frac{m}{p_1A} \\= \frac{1.45}{6.724 \times 0.043 } \\= 5.015m/s[/tex]
The inlet velocity is 5.015
