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You are given two positively charged particles, of equal magnitude, separated by a distance, "d". What will happen to the force field between the two particles when "d" is doubled?

Respuesta :

bhuvna789456

Force becomes 1/4th

Explanation:

  • Force between two positively charged particles is given by the equation

F = k×q1×q2/r² So, force is inversely proportional to square of r.

Here, k is a constant, q1 and q2 are the charges which are equal and r is the distance between them.

  • So if the distance is doubled, r becomes 2r and r² becomes (2r)² = 4r²
  • Force, F then becomes 1/4th of the initial force.

Answer:

c

Explanation:

because i look up the answer

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